SOLUTION: How would you solve the equation .25^x-0.5=2 ?

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Question 294959: How would you solve the equation .25^x-0.5=2 ?
Answer by helpnalgebra(91) About Me  (Show Source):
You can put this solution on YOUR website!
25^(x)-0.5=2
25^(x)=0.5+2
25^(x)=2.5
ln(25^(x))=ln(2.5)
xln(25)=ln(2.5)
xln(25)=(0.92)
(xln(25))/(ln(25))=(0.92)/(ln(25))
x=(0.92)/(ln(25))_xAPPR0.28 answer