SOLUTION: log8(x)+log8(x+2)=1 show that the function f(x)=2x+3 is one to one, by using f(a)=f(b)implies that a=b

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: log8(x)+log8(x+2)=1 show that the function f(x)=2x+3 is one to one, by using f(a)=f(b)implies that a=b      Log On


   

Question 247086: log8(x)+log8(x+2)=1
show that the function f(x)=2x+3 is one to one, by using f(a)=f(b)implies that a=b
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
log8(x)+log8(x+2)=1
8^(log[8](x)) * 8^log[8](x+2)=8^1
x(x+2)=8
x^2+2x-8=0
(x+4)(x-2)=0
x=2 Why isn't x=-4 an answer also?
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Ed