SOLUTION: x=12^(log base 12 of 5) I think that's the same as: x=12^(5 log base 12), but I'm just trying to follow previous patterns and I'm lost

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: x=12^(log base 12 of 5) I think that's the same as: x=12^(5 log base 12), but I'm just trying to follow previous patterns and I'm lost      Log On


   



Question 244987: x=12^(log base 12 of 5)
I think that's the same as:
x=12^(5 log base 12), but I'm just trying to follow previous patterns and I'm lost

Found 2 solutions by dabanfield, jim_thompson5910:
Answer by dabanfield(803) About Me  (Show Source):
You can put this solution on YOUR website!
You are thinking of the rule that log base 12 of 5^n = n * (log base 12 of 5) which doesn't apply here.
The base 12 log of a number, say z, is the power that 12 needs to be raised to to produce the number z:
z = log base 12 of 5 if and only if 12^z = 5 by definition of a log.

In this case x = log base 12 of 5 is the number that 12 would need to be raised to to produce the number 5. So actually raising 12 to the (log base 12 of 5) produces a value of 5.

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
It turns out that a%5Elog%28a%2C%28b%29%29=log%28a%2C%28a%5Eb%29%29=b. In this problem, it's useful to know a%5Elog%28a%2C%28b%29%29=b.


In this case, a=12 and b=5. So x=12%5E%28log%2812%2C%285%29%29%29=5 which means that the answer is x=5