SOLUTION: Solve. include approximations to the nearest thousandth. log(x-3) + logx = 1
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Question 235044
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Solve. include approximations to the nearest thousandth.
log(x-3) + logx = 1
Answer by
solver91311(24713)
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The sum of the logs is the log of the product, that is:
Therefore
If the base is unspecified, base 10 is understood, so:
Apply the definition of logarithms
Put that into standard form and you have a factorable quadratic equation:
or
But
is not in the domain of
, therefore you must exclude this root.
Check
John