SOLUTION: (Please show your work) Change each exponential form to an equivalent logarithmic form: a. {{{32 = 2^5}}} - b. {{{1/125 = 25^(-3/2)}}} - c. {{{12 = 144^(1/2)}}}

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: (Please show your work) Change each exponential form to an equivalent logarithmic form: a. {{{32 = 2^5}}} - b. {{{1/125 = 25^(-3/2)}}} - c. {{{12 = 144^(1/2)}}}       Log On


   

Question 205766: (Please show your work)
Change each exponential form to an equivalent logarithmic form:
a. 32+=+2%5E5
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b. 1%2F125+=+25%5E%28-3%2F2%29
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c. 12++++=+144%5E%281%2F2%29
Answer by Targetweek(62) About Me  (Show Source):
You can put this solution on YOUR website!
1. use this equation for future reference
x+=+b%5Ey then y+=+log%28b%2Cx%29
a. 32=2%5E5
= 5=log%282%2C32%29
b. 1%2F125+=+25%5E%28-3%2F2%29
= -3%2F2+=+log%2825%2C5%29
c. 12++++=+144%5E%281%2F2%29
= 1%2F2+=+log%28144%2C12%29