SOLUTION: Solve for x: log_12 (x-3) + log_12 (x+1)=1
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Question 177040
:
Solve for x: log_12 (x-3) + log_12 (x+1)=1
Answer by
jim_thompson5910(35256)
(
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Start with the given equation.
Take note that
(for the first log) and
(for the second log). So the domain is
(this interval works for both logs)
Note: remember, you cannot take the log of 0 or a negative number.
Combine the logs using the identity
Rewrite the equation using the property:
====>
Raise 12 to the first power to get 12
FOIL
Subtract 12 from both sides.
Combine like terms.
Notice we have a quadratic equation in the form of
where
,
, and
Let's use the quadratic formula to solve for x
Start with the quadratic formula
Plug in
,
, and
Negate
to get
.
Square
to get
.
Multiply
to get
Rewrite
as
Add
to
to get
Multiply
and
to get
.
Take the square root of
to get
.
or
Break up the expression.
or
Combine like terms.
or
Simplify.
So the possible answers are
or
However, since the value
is NOT in the domain
, this means that
is NOT a valid solution.
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Answer:
So the only solution is