SOLUTION: Given that log_3x=2 and log_3y=5, evaluate: log_3 ((27(x^-2)y)

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Question 174939: Given that log_3x=2 and log_3y=5, evaluate:
log_3 ((27(x^-2)y)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Given that log_3x=2 and log_3y=5, evaluate:
log_3 ((27(x^-2)y)
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Problem:
log_3 ((27(x^-2)y) = log3 (27) -2log3 (x) + log3 (y)
= 3 -2(2) + 5
= -4
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Cheers,
Stan H.