SOLUTION: What is the solution to {{{(3^(2x)) + (3^(x+1)) - 4 = 0}}}

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Question 16657: What is the solution to
%283%5E%282x%29%29+%2B+%283%5E%28x%2B1%29%29+-+4+=+0
Answer by rahman(247) About Me  (Show Source):
You can put this solution on YOUR website!
%283%5E%282x%29%29+%2B+%283%5E%28x%2B1%29%29+-+4+=+0
3%5E%282x%29+%2B+3%5Ex%2A3%5E1+-+4+=+0
3%5E%282x%29+%2B+3%5Ex%2A3+-+4+=+0
Suppose: p=3%5Ex, so that:
p%5E2%2Bp%2A3-4=0
p%5E2%2B3p-4=0
(p+4)(p-1)=0
p+4=0 or p-1=0
p=-4 or p=1
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substitute p=-4 to p=3%5Ex:
p=3%5Ex
-4=3%5Ex ------>There is no solution for x
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Substitute p=1 to p=3%5Ex:
p=3%5Ex
1=3%5Ex
3%5E0=3%5Ex
x=0
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Thus, solution for this problem is x = 0