SOLUTION: Tutor please help me? Simplify log3 64/log3 16

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Question 145261: Tutor please help me?
Simplify log3 64/log3 16
Found 2 solutions by stanbon, Alan3354:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify log3 64/log3 16
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Using loga b = (logc b)/(logc a) you have:
[(log2 64)/(log2 3)] / [(log2 16)/(log2 3]
The log2 3 factors cancel and you have:
= [ 6/1] / [4/1]
= 6/4
= 3/2
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Cheers,
Stan H.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
64 = 16 times sqrt(16) = 16%5E1.5
So the log(64)/log(16) = 1.5 with any base.