SOLUTION: I follow along to a point, but some things stump me. Would you show me how to solve lnA = lnH-ln(1-H)

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Question 128491: I follow along to a point, but some things stump me. Would you show me how to solve lnA = lnH-ln(1-H)
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
taking antilog __ A=H/(1-H)

multiplying by 1-H __ A-AH=H

adding AH __ A=H+AH

factoring __ A=H(1+A)

dividing (1+A) __ A/(1+A)=H