SOLUTION: IF 3LOG1.2 + 2LOG 1/3SQUARE ROOT 10 - LOG20=LOGN. FIND N

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Question 1210713: IF 3LOG1.2 + 2LOG 1/3SQUARE ROOT 10 - LOG20=LOGN. FIND N
Found 3 solutions by timofer, josgarithmetic, greenestamps:
Answer by timofer(161) About Me  (Show Source):
You can put this solution on YOUR website!
Write it correctly. Don't make people guess.

Answer by josgarithmetic(39847) About Me  (Show Source):
You can put this solution on YOUR website!
You may have an ambiguous part.
I'll assume you have this:

3*log(1.2)+2*log(1/(3*sqrt(10)))-log(20)=log(N)

and then

log(1.2^3)+log((1/(3*sqrt(10)))^2)-log(20)=log(N)
more steps, omitting here.
.
.
log(1.728)-log(1800)=log(N)

log(1.728/1800)=log(N)

log(0.00096)=log(N)


N=0.00096

(possible mistakes; did not recheck)

Answer by greenestamps(13391) About Me  (Show Source):
You can put this solution on YOUR website!




Using basic rules of logarithms, we have

N=%28%28%281.2%29%5E3%29%28%28sqrt%2810%29%2F3%29%5E2%29%29%2F20

N=%28%281.2%29%281.2%29%281.2%29%2810%29%29%2F%283%2A3%2A20%29

N=%28%281.2%29%28.4%29%28.4%29%29%2F2

N=%28.6%29%28.4%29%28.4%29

N=.096

ANSWER: N = .096