Question 1209825: Log4 base2+log9 base3
Answer by CPhill(1959)   (Show Source):
You can put this solution on YOUR website! Let's evaluate the given expression:
log₄(2) + log<0xE2><0x82><0x89>(3)
**1. Evaluate log₄(2):**
* We want to find the power to which we must raise 4 to get 2.
* 4^(1/2) = √4 = 2
* Therefore, log₄(2) = 1/2
**2. Evaluate log<0xE2><0x82><0x89>(3):**
* We want to find the power to which we must raise 9 to get 3.
* 9^(1/2) = √9 = 3
* Therefore, log<0xE2><0x82><0x89>(3) = 1/2
**3. Add the Results:**
* log₄(2) + log<0xE2><0x82><0x89>(3) = 1/2 + 1/2 = 1
**Therefore, log₄(2) + log<0xE2><0x82><0x89>(3) = 1**
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