SOLUTION: Solve for x: log₆(x+13) + log₆(-x) = 2

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Question 1200049: Solve for x:
log₆(x+13) + log₆(-x) = 2
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

+log%286%2C+%28x%2B13%29+%29%2B+log%286%2C+%28-x%29%29+=+2

+log%286%2C+%28%28x%2B13%29%28-x%29%29+%29=+2

+log%28%28x%2B13%29%28-x%29%29+%2Flog%286%29%29=+2

+log%28%28%28x%2B13%29%28-x%29%29%29+=+2log%286%29

+log%28%28%28x%2B13%29%28-x%29%29%29+=+log%28%286%5E2%29%29

+log%28%28%28x%2B13%29%28-x%29%29%29+=+log%28%2836%29%29

then
+%28x%2B13%29%28-x%29+=+36
+-x%5E2+-+13x+=+36
+0+=+x%5E2+%2B13x%2B36
+%28x+%2B+9%29+%28x+%2B+4%29=0

Solutions:
+x+=-9
+x+=-4