SOLUTION: log2(x+2)+log2(x-2)=5

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Question 1195587: log2(x+2)+log2(x-2)=5
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
log%282%2C%28x%2B2%29%29+%2B+log%282%2C%28x-2%29%29+=+5
which is
log%282%2C%28x%2B2%29%28x-2%29%29++=+5
Foil
log%282%2C%28x%5E2-4%29%29++=+5
exponent equiv of logs
x%5E2+-+4+=+2%5E5
x%5E2+-+4+=+32
x%5E2+-+4+-+32+=+0
x%5E2+-+36+=+0
factors to
(x-6)(x+6) = 0
Two solutions but only the positive one works in the original problem
x = 6