SOLUTION: Let a=log2 and b=log3, compute log3√2√2+ log5√3 3√3.

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Question 1177653: Let a=log2 and b=log3, compute log3√2√2+ log5√3 3√3.
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20855) About Me  (Show Source):
You can put this solution on YOUR website!
Let a=log%28%282%29%29 and b=log%28%283%29%29,
compute log3√2√2+ log5√3 3√3 ???->here is not quite clear what is given

assuming you have

log%28%283sqrt%282%29sqrt%282%29%29%29%2B+log%28%285sqrt%283%29+%2A3sqrt%283%29%29%29

log%28%283%28sqrt%282%29%29%5E2%29%29%2B+log%28%285%2A3%28sqrt%283%29%29%5E2%29%29

log%28%283%2A2%29%29%2B+log%28%285%2A3+%2A3%29%29



log%28%282%29%29%2B3log%28%283%29%29%2B+log%28%285%29%29+

a%2B+3b%2Blog%28%285%29%29




Answer by MathTherapy(10895) About Me  (Show Source):
You can put this solution on YOUR website!
Let a=log2 and b=log3, compute log3√2√2+ log5√3 3√3.
**********************************************
If a = log (2) and b = log (3), and log (3√2√2) + log (5√3*3√3) needs to be computed, then:
 = log+%28%283%28sqrt%282%29%29%5E2%29%29+%2B+log+%28%285%2A3%2A%28sqrt%283%29%29%5E2%29%29
                                                  = log+%28%283+%2A+2%29%29+%2B+log+%28%285%2A3%2A3%29%29
                                                  = log+%28%283+%2A+2%29%29+%2B+log+%28%28%2810%2F2%29%283%5E2%29%29%29
                                                  = 
                                                  = 
                                                  = 3+log+%283%29+%2B+1
                                                  = 3b + 1 ---- Substituting b for log (3)