SOLUTION: https://imgur.com/a/U6PJIau then x^-1/2 equals...

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: https://imgur.com/a/U6PJIau then x^-1/2 equals...      Log On


   



Question 1153083: https://imgur.com/a/U6PJIau then x^-1/2 equals...
Found 3 solutions by MathLover1, ikleyn, MathTherapy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
log%287%2C%28log%283%2C%28log%282%2Cx%29%29%29%29%29=0

log%28%28log%283%2C%28log%28x%29%2Flog%282%29%29%29%29%29%2Flog%287%29=0

log%28%28log%28%28log%28x%29%2Flog%282%29%29%2Flog%283%29%29%29%29%2Flog%287%29=0






%28log%28log%28log%28x%29%29+-+log%28log%282%29%29%29+-+log%28log%283%29%29%29+=+0


log%28%28log%28log%28x%29%2Flog%282%29%29%29%29+=log%28%28log%283%29%29%29.......if log same

log%28%28log%28x%29%2Flog%282%29%29%29+=+log%283%29.......if log same

log%28x%29%2Flog%282%29+=+3

log%28x%29+=+3log%282%29

log%28x%29+=+log%282%5E3%29

log%28x%29+=+log%288%29.......if log same

x=8



Answer by ikleyn(52908) About Me  (Show Source):
You can put this solution on YOUR website!
.
If   log%287%2C%28log%283%2C%28log%282%2C%28x%29%29%29%29%29%29 = 0,   find   x^(-1/2).
~~~~~~~~~~~~~~~


1)  Since   log%287%2C%28log%283%2C%28log%282%2C%28x%29%29%29%29%29%29 = 0,    it implies   log%283%2C%28log%282%2C%28x%29%29%29%29 = 1.



2)  Since    log%283%2C%28log%282%2C%28x%29%29%29%29 = 1,   it implies    log%282%2C%28x%29%29 = 3.



3)  Since    log%282%2C%28x%29%29 = 3,   it implies  x = 2%5E3 = 8.



ANSWER.    x^(-1/2) = 8^(-1/2) = 1%2Fsqrt%288%29= 1%2F%282%2Asqrt%282%29%29 = sqrt%282%29%2F4.


Solved and completed.

This way is a standard method of solving such problems.

---------------

May the angel of Mathematics saves you from solving this problem in a way as @MathLover1 does it.



Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!

https://imgur.com/a/U6PJIau then x^-1/2 equals...
I TOTALLY agree with TUTOR @IKLEYN. 
I would pray to the Lords that they get me through SUPPOSED solutions by that person who claims to love math.


matrix%281%2C3%2C+log%283%2C+%28log%282%2C+%28x%29%29%29%29%2C+%22=%22%2C+7%5E0%29 ----- Converting to EXPONENTIAL form
matrix%281%2C3%2C+log%283%2C+%28log%282%2C+%28x%29%29%29%29%2C+%22=%22%2C+1%29
matrix%281%2C3%2C+log%282%2C+%28x%29%29%2C+%22=%22%2C+3%5E1%29 ----- Converting to EXPONENTIAL form
matrix%281%2C3%2C+log%282%2C+%28x%29%29%2C+%22=%22%2C+3%29
matrix%281%2C3%2C+x%2C+%22=%22%2C+2%5E3%29 ----- Converting to EXPONENTIAL form
matrix%281%2C3%2C+x%2C+%22=%22%2C+8%29



That's IT!!!