SOLUTION: I have tried everything and I just don't understand this problem. Here is the problem {{{log(6,36)}}} = {{{5x + 3}}}

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Question 114659: I have tried everything and I just don't understand this problem.
Here is the problem
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Found 2 solutions by edjones, Edwin McCravy:
Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website!
log(6)36=(5x+3)
36=6^(5x+3)
6^2=6^(5x+3)
Since the base (6) is the same for all exponents we can make an equation of the exponents:
2=5x+3
5x=-1
x=-1/5
Check:
2=5*-1/5+3
2=-1+3 true
Ed

Answer by Edwin McCravy(20056) (Show Source):
You can put this solution on YOUR website!
I have tried everything and I just don't understand this problem.
Here is the problem
=
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We use the definition of a logarithm:
which says this:
The equation logA = C
is equivalent to this equation
B^C = A
That means that your equation:
=
is equivalent to and can be replaced by
the equation:
=
Now since 6�6=36, we can write 36 as 6^{2

=

Now since the base 6 is positive and not equal to 1,

we can equate the exponents of 6 on both sides:

=

=

=

=

Edwin}