SOLUTION: I need help with 2 problems using my new TI-84 Plus: 1.find x: log x=3.8893 The answer I got was:.5898714436 Is this correct? 2.find x: log x = -1.5003 I enter LOG(-1.5003)

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Question 113440: I need help with 2 problems using my new TI-84 Plus:
1.find x: log x=3.8893
The answer I got was:.5898714436 Is this correct?
2.find x: log x = -1.5003
I enter LOG(-1.5003) enter and I get an error:syntax message Help!!
Found 2 solutions by edjones, josmiceli:
Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website!
Remember:
log[a]x=y
x=a^y
.
1)
log[10]x=3.8893
x=10^3.8893
x=7749.97
.
2)
log[10]x=-1.5003
x=10^-1.5003=1/10^1.5003
x=.031601
.
Ed

Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!
You don't quite have the right idea. Always remember
"logs are exponents" end of story.
So, when you see log(result) =
Whatever is on the other side of the "=" sign is the exponent
The (result) is what you get when you raise the base to that exponent
Let's look at the 1st problem
log(result) = 3.8893
If 3.8893 is the exponent, and the base is 10, I get
since the (result) is
I get
------------------
2nd problem
log(result) = - 1.5003