SOLUTION: Rachel Spender wants to invest $4000 in savings certificates which bear an interest rate of 7.25% compounded semi-anually. How long a time period should she choose in order to save

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Rachel Spender wants to invest $4000 in savings certificates which bear an interest rate of 7.25% compounded semi-anually. How long a time period should she choose in order to save      Log On


   



Question 1111913: Rachel Spender wants to invest $4000 in savings certificates which bear an interest rate of 7.25% compounded semi-anually. How long a time period should she choose in order to save an amount of $4700?
Answer by MathTherapy(10801) About Me  (Show Source):
You can put this solution on YOUR website!
Rachel Spender wants to invest $4000 in savings certificates which bear an interest rate of 7.25% compounded semi-anually. How long a time period should she choose in order to save an amount of $4700?
*****************************************************
Future-value-of-$1 formula: A+=+P%281+%2B+i%2Fm%29%5E%28mt%29, with A = Future Value (Unknown, in this case)
                                                                                        P = Principal/Initial Deposit ($4,000, in this case)
                                                                                        i = Interest rate, as a decimal (7.25%, or .0725, in this case)
                                                                                        m = Number of ANNUAL compounding periods (semiannually, or 2, in this case)
                                                                                        t = Time Principal/Initial Deposit has been invested, in YEARS (t, in this case)

How long a time period should she choose in order to save an amount of $4700?

                                                                       A+=+P%281+%2B+i%2Fm%29%5E%28mt%29 
                                                               %224%2C700%22+=+%224%2C000%22%281+%2B+.0725%2F2%29%5E%282t%29 ----- Substituting $4,700 for A, $4,000 for P, .0725 for i, and 2 for m 
                                                               %224%2C700%22%2F%224%2C000%22+=+%281+%2B+.0725%2F2%29%5E%282t%29
                                                                     47%2F40+=+%281.03625%29%5E%282t%29
                                                                     2t+=+log+%28%281.03625%29%2C+%2847%2F40%29%29 ----- Converting to LOGARITHMIC form
Time it'll take the $4,000 investment to increase to $4,700, or t+=+highlight%28%28log+%281.03625%2C+%2847%2F40%29%29%2F2%29%29 = 2.26446601 years, which needs to be ROUNDED UP
                                                                                                                                                             to 2%261%2F2 years, or 2 years, 6 months.
 
** Notice that although 2.26446601 rounds off to about 2%261%2F4 years, the $4,000 investment, at the 2%261%2F4-year juncture, will increase to about
$4,695.16 (< $4,700). This is why it's necessary to ROUND UP to year 2%261%2F2, or 2.5 years (at the semi-annual point), at which time, the $4,000 
initial deposit will exceed $4,700 (about $4,779.50, to be exact).