If log 4=0.6021 and log 6=0.7782 find log 0.096
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log 4 = 0.6021 ; log 6 = 0.7782
log 0.096 =
= log (96) - log (1,000)
= log (16 * 6) - log (1,000)
= log (16) + log (6) - log (1,000)
= log (42) + log (6) - log (103)
= 2 log (4) + log (6) - 3
= 2(0.6021) + 0.7782 - 3 ---- Substituting 0.6021 for log (4), and 0.7782 for log (6)
= 1.2042 + .7782 - 3 = 1.9824 - 3 = - 1.0176