SOLUTION: With log 2 = .301 and log 3=.477. How am I suppose to find log .006 with those?

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Question 1109946: With log 2 = .301 and log 3=.477. How am I suppose to find log .006 with those?
Answer by ikleyn(52814) About Me  (Show Source):
You can put this solution on YOUR website!
.
0.006 = %282%2A3%29%2F1000.


Therefore,  log(0.006) = log(2) + log(3) - log(1000) = log(2) + log(3) - 3 

                       = substitute the given values for log(2)  and  log(3)  and calculate.