SOLUTION: I have this problem: 4log(base6)x=log(base6)64. My answer was x=64^1/4. I was hesitant to go with this answer because my textbook had no examples that ended in an answer like that.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I have this problem: 4log(base6)x=log(base6)64. My answer was x=64^1/4. I was hesitant to go with this answer because my textbook had no examples that ended in an answer like that.      Log On


   

Question 1102961: I have this problem: 4log(base6)x=log(base6)64. My answer was x=64^1/4. I was hesitant to go with this answer because my textbook had no examples that ended in an answer like that. Is this correct? If not, how do I solve this correctly? Thanks!1/4
Answer by greenestamps(13215) About Me  (Show Source):
You can put this solution on YOUR website!


Solving the equation is rather easy, since we have log base 6 on both sides.

We get x%5E4=64, so your answer 64%5E%281%2F4%29 is valid.

However, it can be simplified in many ways, without resorting to an irrational approximation obtained with a calculator.



All of those forms are equivalent. In most situations either 2%5E%283%2F2%29 or 2%2Asqrt%282%29 would be considered the best forms.