Question 1076081: solve log base 5(x+2) + log base 8(x+4) = log abse 8(2) + log base 8(4) Found 2 solutions by stanbon, MathTherapy:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! solve log base 8(x+2) + log base 8(x+4) = log abse 8(2) + log base 8(4)
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log8[(x+2)(x+4)] = log8[2*4]
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x^2+6x+8 = 8
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x^2+6x = 0
x(x+6) = 0
x = 0 is the only acceptable answer
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Cheers,
Stan H.
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solve log base 5(x+2) + log base 8(x+4) = log abse 8(2) + log base 8(4)
Does this start with: log5(x + 2) or log8(x + 2)?
The person who responded has the latter. Does he know something I don't?
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