SOLUTION: h(x)=log1/8(x+2)+5 sketch the graph, find two points on the graph and determine the domain and axis of any vertical asymptotes

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Question 1075957: h(x)=log1/8(x+2)+5
sketch the graph, find two points on the graph and determine the domain and axis of any vertical asymptotes

Answer by Theo(13342) (Show Source):
You can put this solution on YOUR website!
you can use the log base conversion formula to convert this to log10.

you will get:

log(x+2) to the base of 1/8 + 5 is equal to log(x+2)/log(1/8) + 5

now you can use your calculator to find some points and then draw a graph.

or, .....

you can use the following online graphing sofware that will do the job for you.

https://www.desmos.com/calculator

your graph will look like this:

you will have a vertical asymptote at x = -2.

when x = -2, log(x+2) becomes equal to log(0) which is not valid since the log function requires an argument that is greater than 0.

therefore x has to be greater than -2.