SOLUTION: Solve: Log5(2x+1)+Log5(x+2)=1

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Question 1075548: Solve:
Log5(2x+1)+Log5(x+2)=1
Found 2 solutions by Lightning_Fast, josgarithmetic:
Answer by Lightning_Fast(78) About Me  (Show Source):
You can put this solution on YOUR website!
Remember the log rule
logx%283%29%2Blogx%284%29=log%283%2A4%29
Thus
log5%282x%2B1%29%2Blog5%28x%2B2%29=1
log5%282x%5E2%2B4x%2Bx%2B2%29=1
5%5E1=2x%5E2%2B5x%2B2
Now just factor and solve from x there. Hope this helped.

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Unclear but intent could be base five.

log%285%2C%282x%2B1%29%29%2Blog%285%2C%28x%2B2%29%29=1
log%285%2C%282x%2B1%29%28x%2B2%29%29=1
5%5E1=%282x%2B1%29%28x%2B2%29

2x%5E2%2B5x%2B2-5=0

2x%5E2%2B5x-3=0

%282x-1%29%28x%2B3%29=0

x=1%2F2