SOLUTION: If a^x=bc;b^y=ca;c^z=ab then prove x/(x+1) + y/(y+1) + z/(z+1) =2

To avoid doing essentially the same thing three times, 
I'll just do it once with the letters p,q,r,s and use it as
a formula for each of the fractions:






Therefore,



and therefore, using the above as a formula,





Edwin