SOLUTION: Determine the domain of the function f(x) = ln (4x-x^2) I've gotten the inequality of the function which is 4x-x^2>0 but I still can't figure out what the domain is

Question 1064212: Determine the domain of the function f(x) = ln (4x-x^2)
I've gotten the inequality of the function which is 4x-x^2>0 but I still can't figure out what the domain is
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
graph 4x-x^2 and look for the part where f(x) > 0.

4x-x^2 must be greater than 0. ln (0) does not exist, nor does ln of a negative number
Therefore, -x^2+4x=0
same as x^2-4x=0
x*(x-4)=0
x=0 (not allowed)
x=4 (not allowed)
Need to test x between 0 and 4. Try 1,2,3
for 1, ln (3)
for 2, ln (4)
for 3, ln (3)
Try 5
ln (20-25) does not work.
Domain is 0 < x < 4

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