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Please help I'm having trouble trying to solve logarithm equation log(y+2)=1-log (2y-6)
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log(y+2) = 1 - log (2y-6) ---> log(y+2) + log (2y-6) = 1 ---> (y+2)*(2y-6) = 10.
Can you solve this quadratic equation ?
When you complete solution, check if the roots suit under logarithms.
