SOLUTION: logarithmic expression for x log12 x/30=2 Says you can also convert to an exponential equation but isn't required. Which way is easier and how would you do both?

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: logarithmic expression for x log12 x/30=2 Says you can also convert to an exponential equation but isn't required. Which way is easier and how would you do both?      Log On


   



Question 1061991: logarithmic expression for x
log12 x/30=2
Says you can also convert to an exponential equation but isn't required.
Which way is easier and how would you do both?

Found 2 solutions by math_helper, MathTherapy:
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
log12 (x/30) = 2

Use this to convert to base e: log_b( n ) = ln( n ) / ln(b)

+ln%28x%2F30%29%2Fln%2812%29+=+2+
++ln%28x%2F30%29+=+2%2Aln%2812%29+
++e%5Eln%28x%2F30%29+=+e%5E%282%2Aln%2812%29%29+ (convert to exponential, e^(both sides))
+++x%2F30+=+144+
++x+=+30%2A144+
++x+=+4320++

Ans: x=4320

Check: log12(4320 / 30) = log12(144) = 2 (ok)

Sorry, forgot to address the question about not using exponential. The only ways (that I can see) without using exponentiation would be to use trial-and-error or to reason it out. For example, one can ask this question log12(n) = 2, what is n? Well, n has to be 144 because 12^2 = 144. With that knowledge, one can say what x is, given x/30 = 144? x = 30*144 = 4320. However, this approach probably gets more challenging if the exponent is not an integer :-)




Answer by MathTherapy(10557) About Me  (Show Source):
You can put this solution on YOUR website!
logarithmic expression for x
log12 x/30=2
Says you can also convert to an exponential equation but isn't required.
Which way is easier and how would you do both?
Easier method: 
log+%2812%2C+%28x%2F30%29%29+=+2
x%2F30+=+12%5E2 ------- Converting to EXPONENTIAL form
 ----- Cross-multiplying


LOGARITHMIC method: 
log+%2812%2C+%28x%2F30%29%29+=+2
%28log+%28x%2F30%29%29%2Flog+%2812%29+=+2 ------- Applying change-of-base
log+%28x%2F30%29+=+2log+%2812%29 ----- Cross-multiplying
log+%28x%2F30%29+=+log+%2812%29%5E2 ----- Applying alog+%28b%29+=+log+%28b%29%5Ea
x%2F30+=+12%5E2 ------- If log a = log b, then a  = b
 ----- Cross-multiplying