SOLUTION: I'm trying to get this expression down to a single logarithm. 1/4 log (x-2) - log(x) + log 8 log (x-2)^1/4 - (log x - log 8) log x-2- log x- 8 Is any of the right so far?

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I'm trying to get this expression down to a single logarithm. 1/4 log (x-2) - log(x) + log 8 log (x-2)^1/4 - (log x - log 8) log x-2- log x- 8 Is any of the right so far?       Log On


   

Question 1056592: I'm trying to get this expression down to a single logarithm.
1/4 log (x-2) - log(x) + log 8
log (x-2)^1/4 - (log x - log 8)
log x-2- log x- 8 Is any of the right so far?
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I'm trying to get this expression down to a single logarithm.
1/4 log (x-2) - log(x) + log 8
log (x-2)^1/4 - (log x - log 8)
==========
You were ok, but then what happened to the 1/4?
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log x-2- log x- 8 Is any of the right so far?
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1/4 log (x-2) - log(x) + log 8
= log%28root%284%2C%28x-2%29%29%29+-+log%28x%29+%2B+log%288%29
= log%288%2Aroot%284%2C%28x-2%29%29%29+-+log%28x%29
= log%288%2Aroot%284%2C%28x-2%29%29%2Fx%29
===========
PS x > 2