SOLUTION: Good Afternoon ! How would I solve these two equations? {{{2^(x+1)=5}}} and {{{e^(3x)=12}}} Thank you so much

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Question 1043520: Good Afternoon !
How would I solve these two equations?
2%5E%28x%2B1%29=5
and
e%5E%283x%29=12
Thank you so much
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
2%5E%28x%2B1%29=5
(x+1)*log(2) = log(5)
and
e%5E%283x%29=12
3x = ln(12)