SOLUTION: Solve for x if log_4 x-1+log_4 (x-1)=0

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Question 1042896: Solve for x if log_4 x-1+log_4 (x-1)=0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
log%284%2C%28x-1%29%29%2Blog%284%2C%28x-1%29%29=0
2%2Alog%284%2C%28x-1%29%29=0
log%284%2C%28x-1%29%5E2%29=0
%28x-1%29%5E2=1
x-1=0+%2B-+1
x=2 and x=0
However when x=0 you get a negative log argument which is not allowed.
So,
x=2 is the only solution.