SOLUTION: -1+10log2(4t+5)=19

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Question 1039383: -1+10log2(4t+5)=19
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
-1+%2B+10log%282%2C%284t%2B5%29%29=19
10log%282%2C%284t%2B5%29%29=19%2B1
10log%282%2C%284t%2B5%29%29=20
divide both sides by 10
log%282%2C%284t%2B5%29%29=2
The exponent equiv of logs
(4t+5) = 2^2
4t + 5 = 4
4t = 4 - 5
4t = -1
t = -1/4
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Check solution in the original equation
-1+%2B+10log%282%2C%284%28-1%2F4%29%2B5%29%29=19
-1+%2B+10log%282%2C%28-1%2B5%29%29=19
-1+%2B+10log%282%2C4%29=19
log base 2 of 4 is 2, therefore
-1 + 10(2) = 19