Question 1027681: How do you find x and y intercepts of a logarithmic function?
Ex. y=log(-2x+2)-1 Found 2 solutions by FrankM, mananth:Answer by FrankM(1040) (Show Source):
You can put this solution on YOUR website! y=log(-2x+2)-1
For the y intercept, X=0, and
y=log(-2(0)+2)-1
y=log(2)-1
The log of 2 is .301, and .301 - 1 = -.699
To solve for y=0
0=log(-2x+2)-1
1=log(-2x+2)
rearrange
10^(-2x+2)=1
Any non-zero number raised to the zero power equals 1, so
(-2x+2)=0
and X=-4
Here is the Very Cool Graph(tm) for this function
