SOLUTION: Write the following in logarithmic form: 2e^x=1

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Question 1022087: Write the following in logarithmic form: 2e^x=1
Answer by Boreal(15235) About Me  (Show Source):
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ln(2)+ln(e^x)=ln(1)
ln(2)+x=0
x=-ln(2)
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alternative
e^x=(1/2)
ln of both sides
x=0-ln(2)=-ln(2)