Questions on Geometry: Geometric formulas answered by real tutors!

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Question 1192229: A plane slices a right circular cone parallel to its base at the midpoint of its height. The radius of the cone is 4 in. and its height is 12 in. Find the volume of the figure BELOW the plane. ​
Click here to see answer by MathLover1(20850) About Me 
Question 1192229: A plane slices a right circular cone parallel to its base at the midpoint of its height. The radius of the cone is 4 in. and its height is 12 in. Find the volume of the figure BELOW the plane. ​
Click here to see answer by ikleyn(52786) About Me 

Question 1192226: The midpoint of all sides of the square is all joined together to create another square inside it (see figure below). If the area of the smaller square is given as 100 m2, find the area of the bigger square. ​
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Question 1192228: A right, regular triangular prism has a circular cylinder inscribed in it (see figure to see the top side of the figure). If the prism has an edge of 6in on its base and height of 2in. Find the volume of the cylinder inside. ​
Click here to see answer by greenestamps(13200) About Me 

Question 1192518: △ABC lies in the structural support system of the Ferris wheel.
If m∠A = 30° and AB = AC = 25 ft,
find the measures (in degrees) of ∠B and ∠C.
BASE ANGLE (Angle B) + VERTEX ANGLE (ANGLE A)+ SECOND BASE ANGLE (Angle C) = 180 and the fact that we again have an isosceles triangle, making Angle B and Angle C the same measure.

Click here to see answer by ikleyn(52786) About Me 

Question 1192515: can i get some help with this question.
If
VU ≅ VT and m∠V = 50°,
find m∠T (in degrees).
we have an ISOSCELES TRIANGLE and as we learned in earlier chapters all of the angles within a triangle MUST add to 180 degrees. So we have an equation Angle V + Angle U + Angle T = 180 , Furthermore, since we have an ISOSCELES triangle, one of the rules is the BASE ANGLES - Angle T and ANGLE U - are EQUAL (the same). If you do the substitution ,you will find the angular measure of Angle T, which is also the value of ANGLE U

Click here to see answer by ikleyn(52786) About Me 

Question 1192516: If
m∠T = m∠U = (2x)°,
find m∠V (in degrees) as an expression containing variable x.

we again have an ISOSCELES TRIANGLE, and as we learned in earlier chapters all of the angles within a triangle MUST add to 180 degrees. So we have an equation Angle V + Angle U + Angle T = 180 , Furthermore, since we have an ISOSCELES triangle, one of the rules is the BASE ANGLES - Angle T and ANGLE U - are EQUAL (the same). If you do the substitution ,you will find the angular measure of Angle V ... NOTE: Yes, this answer will have a variable. :)

Click here to see answer by ikleyn(52786) About Me 

Question 1192576: Because of construction along the road from A to B, Alinna drives 8 miles from A to C and then 15 miles from C to B.
How much farther (in miles) did Alinna travel by using the alternative route from A to B?
This problem has a RIGHT angle .... so when a RIGHT ANGLE occurs ... the Pythagorean theorem will be needed in this problem. Once you use the Pythagorean theorem ... you will get the length of AB ... but this question goes a little further ... it wants the DIFFERENCE of AB from the SUM of AC and CB

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Question 1192573: A surveyor knows that a lot has the shape of an isosceles triangle. If the vertex angle measures 80° and each equal side is 160 feet long, what measure (in degrees) does each of the base angles have?

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Question 1192575: If
m∠T = m∠U = (2x)°,
find m∠V (in degrees) as an expression containing variable x
So we have an equation Angle V + Angle U + Angle T = 180 .... Furthermore, since we have an ISOSCELES triangle, one of the rules is the BASE ANGLES - Angle T and ANGLE U - are EQUAL (the same). If you do the substitution ... .you will find the angular measure of Angle V ... NOTE: Yes, this answer will have a variable

Click here to see answer by ikleyn(52786) About Me 

Question 1192574: If
VU ≅ VT and m∠V = 50°,
find m∠T (in degrees).
So we have an equation Angle V + Angle U + Angle T = 180 .... Furthermore, since we have an ISOSCELES triangle, one of the rules is the BASE ANGLES - Angle T and ANGLE U - are EQUAL (the same). If you do the substitution ... .you will find the angular measure of Angle T ... which is also the value of ANGLE U

Click here to see answer by ikleyn(52786) About Me 

Question 1192578: In a ISOSCELES TRIANGLE
m∠T = m∠U = (2x)°,
find m∠V (in degrees) as an expression containing variable x
Yes, this answer will have a variable.

Click here to see answer by ikleyn(52786) About Me 

Question 1192600: in a ISOSCELES TRIANGLE If VU ≅ VT and m∠V = 50°,
find m∠T (in degrees).
measure of Angle T , which is also the value of ANGLE U

Click here to see answer by ikleyn(52786) About Me 

Question 1192572: In concave quadrilateral ABCD, the angle at A measures 44°. △ABD is isosceles,
BC bisects ∠ABD,
and DC bisects ∠ADB.
we have an ISOSCELES TRIANGLE, but we are given the VERTEX ANGLE (which is ANGLE A and it equals 44 degrees). Now again, we need to begin with is equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180. If you make both base angles a variable ... and the vertex angle 80 .... you will find the value of 'x' ... which is a base angle. Now, once you obtain the BASE ANGLE ... you need to "BISECT" these base angles ... because this will give you the measure of angle ABC and ADC ...
Then you need to take the "small" triangle inside the bigger triangle (ABD) ... you again use the equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180, but the base angles will be your answer for BISECTED angles ... which, in turn, will give you angle 1

Click here to see answer by Edwin McCravy(20056) About Me 
Question 1192572: In concave quadrilateral ABCD, the angle at A measures 44°. △ABD is isosceles,
BC bisects ∠ABD,
and DC bisects ∠ADB.
we have an ISOSCELES TRIANGLE, but we are given the VERTEX ANGLE (which is ANGLE A and it equals 44 degrees). Now again, we need to begin with is equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180. If you make both base angles a variable ... and the vertex angle 80 .... you will find the value of 'x' ... which is a base angle. Now, once you obtain the BASE ANGLE ... you need to "BISECT" these base angles ... because this will give you the measure of angle ABC and ADC ...
Then you need to take the "small" triangle inside the bigger triangle (ABD) ... you again use the equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180, but the base angles will be your answer for BISECTED angles ... which, in turn, will give you angle 1

Click here to see answer by MathTherapy(10552) About Me 
Question 1192572: In concave quadrilateral ABCD, the angle at A measures 44°. △ABD is isosceles,
BC bisects ∠ABD,
and DC bisects ∠ADB.
we have an ISOSCELES TRIANGLE, but we are given the VERTEX ANGLE (which is ANGLE A and it equals 44 degrees). Now again, we need to begin with is equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180. If you make both base angles a variable ... and the vertex angle 80 .... you will find the value of 'x' ... which is a base angle. Now, once you obtain the BASE ANGLE ... you need to "BISECT" these base angles ... because this will give you the measure of angle ABC and ADC ...
Then you need to take the "small" triangle inside the bigger triangle (ABD) ... you again use the equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180, but the base angles will be your answer for BISECTED angles ... which, in turn, will give you angle 1

Click here to see answer by Alan3354(69443) About Me 

Question 1192599: In concave quadrilateral ABCD, the angle at A measures 44°. △ABD is isosceles,
BC bisects ∠ABD,
and DC bisects ∠ADB
What are the measures (in degrees) of
∠ABC, ∠ADC, and ∠1?
we have a ISOSCELES TRIANGLE, but we are given the VERTEX ANGLE (which is ANGLE A and it equals 44 degrees). Now again, we need to begin with is equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180. If you make both base angles a variable ,and the vertex angle 80 ,you will find the value of 'x' , which is a base angle. Now, once you obtain the BASE ANGLE , you need to "BISECT" these base angles, because this will give you the measure of angle ABC and ADC ,
Then you need to take the "small" triangle inside the bigger triangle (ABD),you again use the equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180, but the base angles will be your answer for BISECTED angles ... which, in turn, will give you angle 1

Click here to see answer by Edwin McCravy(20056) About Me 

Question 1192517: In concave quadrilateral ABCD, the angle at A measures 44°. △ABD is isosceles,
BC bisects ∠ABD,
and DC bisects ∠ADB.
What are the measures (in degrees) of
∠ABC, ∠ADC, and ∠1?
we have an ISOSCELES TRIANGLE, but we are given the VERTEX ANGLE (which is ANGLE A and it equals 44 degrees). Now again, we need to begin with is equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180. If you make both base angles a variable ... and the vertex angle 80 .... you will find the value of 'x' ... which is a base angle. Now, once you obtain the BASE ANGLE ... you need to "BISECT" these base angles ... because this will give you the measure of angle ABC and ADC ...
Then you need to take the "small" triangle inside the bigger triangle (ABD) ... you again use the equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180, but the base angles will be your answer for BISECTED angles ... which, in turn, will give you angle 1

Click here to see answer by ikleyn(52786) About Me 

Question 1192705: Find the number of sides of a polygon whose exterior and interior angles are in the ratio 2:4?
Click here to see answer by Alan3354(69443) About Me 

Question 1192712: In a ISOSCELES TRIANGLE, If
VU ≅ VT and m∠V = 50°,
find m∠T (in degrees)

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Question 1192748: In concave quadrilateral ABCD, the angle at A measures 44°. △ABD is isosceles,
BC bisects ∠ABD, and DC bisects ∠ADB. What are the measures (in degrees) of
∠ABC, ∠ADC, and ∠1?

Click here to see answer by ikleyn(52786) About Me 

Question 1192999: In the figure,
AB = 4x + 1,

BC = 3x + 6,
and
CD = 7x − 5.Find the length of each side of ▱ABCD.
AB =
BC =
CD =
DA =

Click here to see answer by ikleyn(52786) About Me 

Question 1192998: MNPQ is a parallelogram with diagonals
QN and MP.
If
MR = 5(a + 6)
and
MP = 12a + 28,
find MR, RP, and MP.

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Question 1193000: Suppose
m∠A = (2x + 4)°
and
m∠B = (3x − 34)°.
Find the measure of each angle (in degrees) of
▱ABCD.
m∠A =
°
m∠B =
°
m∠C =
°
m∠D =
°

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Question 1193018: The point, line, and plane are considered to be undefined terms in our development of geometry. Look up these words in any dictionary. Are the dictionary definitions clear enough for a precise mathematical development?

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Question 1193019: Are the following possible? If so, how?
A. For exactly one line to be determined by three points.
B. For exactly two lines to be determined by three points.
C. For more than one plane to contain three given points.

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Question 1193036: For a quadrilateral ABCD, the measures of its angles are given below.
m∠A = (x + 14)°
m∠B = (2(x + 2))°
m∠C =
3/2
x − 13
°

m∠D =
7/3
x − 14
°
Find x.
then, Find the measure of each angle (in degrees) of ABCD.


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Question 1193015: 1.Suppose you have n points, no three of which are collinear. How many lines contain two of these n points?
2.If no four of the n points are coplanar, how many planes contain three of the n points?
Hint: (for 1 and 2, generalize in a form of a formula)

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Question 1193037: For a quadrilateral ABCD, the measures of its angles are given below.
m∠A = (x + 14)°
m∠B = (2(x + 2))°
m∠C =
3/2
x − 13
°
m∠D =
7/3
x − 14
°Find x.
then, Find the measure of each angle (in degrees) of ABCD.
I'm not sure where to even start here. here's what I got so far: x+14+2x+4=360..and x+10+2x=360...so x+10=360..and i got 36

Click here to see answer by MathLover1(20850) About Me 

Question 1193066: Consider ▱ABCD.
Suppose:
m∠A = (2x + 4)°
and
m∠B = (3x − 34)°.
Find x.
x =
Find the measure of each angle (in degrees) of
▱ABCD.
m∠A =
°
m∠B =
°
m∠C =
°
m∠D =
°
im not sure where to start here,so far i have x-30 after i factored.

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Question 1193071: Can i get step by step help with this question, not sure where to start here, im getting the wrong answer.
Consider ▱ABCD.
Suppose m∠A = (2x + 4)°and m∠B = (3x − 34)°.
Find x.
Find the measure of each angle (in degrees) of
▱ABCD.
m∠A =
°
m∠B =
°
m∠C =
°
m∠D =

Click here to see answer by josgarithmetic(39617) About Me 

Question 1193073: Can i get step by step help, ive gotten the answer wrong.Consider ▱ABCD.
Suppose:
m∠A = (2x + 4)°
and
m∠B = (3x − 34)°.
Find x.
x =
Find the measure of each angle (in degrees) of
▱ABCD.
m∠A =
°
m∠B =
°
m∠C =
°
m∠D =
°

Click here to see answer by josgarithmetic(39617) About Me 

Question 1193068: MNPQ is a parallelogram with diagonals
QN and MP. If MR = 5(a + 6)
and MP = 12a + 28,
find MR, RP, and MP.
so far i've got 5a+30=12a+28=7a+2

Click here to see answer by MathLover1(20850) About Me 

Question 1193078: m∠A = (2x + 4)°
and
m∠B = (3x − 34)°.
I've found x, i basically did 5x-30=180 and i ended up getting 42.
Find the measure of each angle (in degrees) of
m∠A =
°
m∠B =
°
m∠C =
°
m∠D =

Click here to see answer by josgarithmetic(39617) About Me 
Question 1193078: m∠A = (2x + 4)°
and
m∠B = (3x − 34)°.
I've found x, i basically did 5x-30=180 and i ended up getting 42.
Find the measure of each angle (in degrees) of
m∠A =
°
m∠B =
°
m∠C =
°
m∠D =

Click here to see answer by MathLover1(20850) About Me 

Question 1193079: ▱ABCD
m∠A = (2x + 4)°
and
m∠B = (3x − 34)°.
i found x which i got 42.
Find the measure of each angle (in degrees) of
▱ABCD.
m∠A =
°
m∠B =
°
m∠C =
°
m∠D =
°

Click here to see answer by MathLover1(20850) About Me 
Question 1193079: ▱ABCD
m∠A = (2x + 4)°
and
m∠B = (3x − 34)°.
i found x which i got 42.
Find the measure of each angle (in degrees) of
▱ABCD.
m∠A =
°
m∠B =
°
m∠C =
°
m∠D =
°

Click here to see answer by greenestamps(13200) About Me 

Question 1193077: M and N are the midpoints of sides
RS and RT of △RST, respectively.
Given:
RM = RN = 3x + 1
ST = 7x − 2
m∠R = 60°
Find:
x, RM, and ST

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Question 1193080: In the figure,
AB = 4x + 1,
BC = 3x + 6,
and CD = 7x − 5.Find the length of each side of ▱ABCD.
so far i have gotten the equation, 4x+1=7x-5 and i got x as 2

Click here to see answer by josgarithmetic(39617) About Me 
Question 1193080: In the figure,
AB = 4x + 1,
BC = 3x + 6,
and CD = 7x − 5.Find the length of each side of ▱ABCD.
so far i have gotten the equation, 4x+1=7x-5 and i got x as 2

Click here to see answer by ikleyn(52786) About Me 
Question 1193080: In the figure,
AB = 4x + 1,
BC = 3x + 6,
and CD = 7x − 5.Find the length of each side of ▱ABCD.
so far i have gotten the equation, 4x+1=7x-5 and i got x as 2

Click here to see answer by MathLover1(20850) About Me 

Question 1193067: In the figure,
AB = 4x + 1,
BC = 3x + 6,
CD = 7x − 5.
Find the length of each side of
AB =
BC =
CD =
DA =

Click here to see answer by ikleyn(52786) About Me 

Question 1193076: Consider kite ABCD with
AB ≅ AD and BC ≅ DC.
For kite ABCD,
AB = x/6+ 8,
AD = x/3+ 5,
and BC = x − 2.
Find x.
Determine the length of each side of the kite.
AB =
AD =
BC =
DC =
Find the perimeter of ABCD.

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Question 1193074: In concave kite ABCD, there is an interior angle at vertex B that is a reflex angle.
Given that m∠A = m∠C = m∠D = 40°, find the measure of the indicated reflex angle in degrees.

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Question 1193075: We have a concave kite ABCD, there is an interior angle at vertex B that is a reflex angle.
Given that
m∠A = m∠C = m∠D = 30°
and the length of side
AB
is 8 in, find the length (in INCHES) of
AC

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