Tutors Answer Your Questions about Geometric formulas (FREE)
Question 1192226: The midpoint of all sides of the square is all joined together to create another square inside it (see figure below). If the area of the smaller square is given as 100 m2, find the area of the bigger square.
Click here to see answer by ikleyn(52786)  |
Question 1192518: △ABC lies in the structural support system of the Ferris wheel.
If m∠A = 30° and AB = AC = 25 ft,
find the measures (in degrees) of ∠B and ∠C.
BASE ANGLE (Angle B) + VERTEX ANGLE (ANGLE A)+ SECOND BASE ANGLE (Angle C) = 180 and the fact that we again have an isosceles triangle, making Angle B and Angle C the same measure.
Click here to see answer by ikleyn(52786)  |
Question 1192515: can i get some help with this question.
If
VU ≅ VT and m∠V = 50°,
find m∠T (in degrees).
we have an ISOSCELES TRIANGLE and as we learned in earlier chapters all of the angles within a triangle MUST add to 180 degrees. So we have an equation Angle V + Angle U + Angle T = 180 , Furthermore, since we have an ISOSCELES triangle, one of the rules is the BASE ANGLES - Angle T and ANGLE U - are EQUAL (the same). If you do the substitution ,you will find the angular measure of Angle T, which is also the value of ANGLE U
Click here to see answer by ikleyn(52786)  |
Question 1192516: If
m∠T = m∠U = (2x)°,
find m∠V (in degrees) as an expression containing variable x.
we again have an ISOSCELES TRIANGLE, and as we learned in earlier chapters all of the angles within a triangle MUST add to 180 degrees. So we have an equation Angle V + Angle U + Angle T = 180 , Furthermore, since we have an ISOSCELES triangle, one of the rules is the BASE ANGLES - Angle T and ANGLE U - are EQUAL (the same). If you do the substitution ,you will find the angular measure of Angle V ... NOTE: Yes, this answer will have a variable. :)
Click here to see answer by ikleyn(52786)  |
Question 1192576: Because of construction along the road from A to B, Alinna drives 8 miles from A to C and then 15 miles from C to B.
How much farther (in miles) did Alinna travel by using the alternative route from A to B?
This problem has a RIGHT angle .... so when a RIGHT ANGLE occurs ... the Pythagorean theorem will be needed in this problem. Once you use the Pythagorean theorem ... you will get the length of AB ... but this question goes a little further ... it wants the DIFFERENCE of AB from the SUM of AC and CB
Click here to see answer by ikleyn(52786)  |
Question 1192575: If
m∠T = m∠U = (2x)°,
find m∠V (in degrees) as an expression containing variable x
So we have an equation Angle V + Angle U + Angle T = 180 .... Furthermore, since we have an ISOSCELES triangle, one of the rules is the BASE ANGLES - Angle T and ANGLE U - are EQUAL (the same). If you do the substitution ... .you will find the angular measure of Angle V ... NOTE: Yes, this answer will have a variable
Click here to see answer by ikleyn(52786)  |
Question 1192574: If
VU ≅ VT and m∠V = 50°,
find m∠T (in degrees).
So we have an equation Angle V + Angle U + Angle T = 180 .... Furthermore, since we have an ISOSCELES triangle, one of the rules is the BASE ANGLES - Angle T and ANGLE U - are EQUAL (the same). If you do the substitution ... .you will find the angular measure of Angle T ... which is also the value of ANGLE U
Click here to see answer by ikleyn(52786)  |
Question 1192572: In concave quadrilateral ABCD, the angle at A measures 44°. △ABD is isosceles,
BC bisects ∠ABD,
and DC bisects ∠ADB.
we have an ISOSCELES TRIANGLE, but we are given the VERTEX ANGLE (which is ANGLE A and it equals 44 degrees). Now again, we need to begin with is equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180. If you make both base angles a variable ... and the vertex angle 80 .... you will find the value of 'x' ... which is a base angle. Now, once you obtain the BASE ANGLE ... you need to "BISECT" these base angles ... because this will give you the measure of angle ABC and ADC ...
Then you need to take the "small" triangle inside the bigger triangle (ABD) ... you again use the equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180, but the base angles will be your answer for BISECTED angles ... which, in turn, will give you angle 1
Click here to see answer by Edwin McCravy(20056)  |
Question 1192572: In concave quadrilateral ABCD, the angle at A measures 44°. △ABD is isosceles,
BC bisects ∠ABD,
and DC bisects ∠ADB.
we have an ISOSCELES TRIANGLE, but we are given the VERTEX ANGLE (which is ANGLE A and it equals 44 degrees). Now again, we need to begin with is equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180. If you make both base angles a variable ... and the vertex angle 80 .... you will find the value of 'x' ... which is a base angle. Now, once you obtain the BASE ANGLE ... you need to "BISECT" these base angles ... because this will give you the measure of angle ABC and ADC ...
Then you need to take the "small" triangle inside the bigger triangle (ABD) ... you again use the equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180, but the base angles will be your answer for BISECTED angles ... which, in turn, will give you angle 1
Click here to see answer by MathTherapy(10552)  |
Question 1192572: In concave quadrilateral ABCD, the angle at A measures 44°. △ABD is isosceles,
BC bisects ∠ABD,
and DC bisects ∠ADB.
we have an ISOSCELES TRIANGLE, but we are given the VERTEX ANGLE (which is ANGLE A and it equals 44 degrees). Now again, we need to begin with is equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180. If you make both base angles a variable ... and the vertex angle 80 .... you will find the value of 'x' ... which is a base angle. Now, once you obtain the BASE ANGLE ... you need to "BISECT" these base angles ... because this will give you the measure of angle ABC and ADC ...
Then you need to take the "small" triangle inside the bigger triangle (ABD) ... you again use the equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180, but the base angles will be your answer for BISECTED angles ... which, in turn, will give you angle 1
Click here to see answer by Alan3354(69443)  |
Question 1192599: In concave quadrilateral ABCD, the angle at A measures 44°. △ABD is isosceles,
BC bisects ∠ABD,
and DC bisects ∠ADB
What are the measures (in degrees) of
∠ABC, ∠ADC, and ∠1?
we have a ISOSCELES TRIANGLE, but we are given the VERTEX ANGLE (which is ANGLE A and it equals 44 degrees). Now again, we need to begin with is equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180. If you make both base angles a variable ,and the vertex angle 80 ,you will find the value of 'x' , which is a base angle. Now, once you obtain the BASE ANGLE , you need to "BISECT" these base angles, because this will give you the measure of angle ABC and ADC ,
Then you need to take the "small" triangle inside the bigger triangle (ABD),you again use the equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180, but the base angles will be your answer for BISECTED angles ... which, in turn, will give you angle 1
Click here to see answer by Edwin McCravy(20056)  |
Question 1192517: In concave quadrilateral ABCD, the angle at A measures 44°. △ABD is isosceles,
BC bisects ∠ABD,
and DC bisects ∠ADB.
What are the measures (in degrees) of
∠ABC, ∠ADC, and ∠1?
we have an ISOSCELES TRIANGLE, but we are given the VERTEX ANGLE (which is ANGLE A and it equals 44 degrees). Now again, we need to begin with is equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180. If you make both base angles a variable ... and the vertex angle 80 .... you will find the value of 'x' ... which is a base angle. Now, once you obtain the BASE ANGLE ... you need to "BISECT" these base angles ... because this will give you the measure of angle ABC and ADC ...
Then you need to take the "small" triangle inside the bigger triangle (ABD) ... you again use the equation BASE ANGLE + VERTEX ANGLE+ SECOND BASE ANGLE = 180, but the base angles will be your answer for BISECTED angles ... which, in turn, will give you angle 1
Click here to see answer by ikleyn(52786)  |
Question 1193018: The point, line, and plane are considered to be undefined terms in our development of geometry. Look up these words in any dictionary. Are the dictionary definitions clear enough for a precise mathematical development?
Click here to see answer by ikleyn(52786)  |
Question 1193019: Are the following possible? If so, how?
A. For exactly one line to be determined by three points.
B. For exactly two lines to be determined by three points.
C. For more than one plane to contain three given points.
Click here to see answer by Alan3354(69443)  |
Question 1193015: 1.Suppose you have n points, no three of which are collinear. How many lines contain two of these n points?
2.If no four of the n points are coplanar, how many planes contain three of the n points?
Hint: (for 1 and 2, generalize in a form of a formula)
Click here to see answer by ikleyn(52786)  |
Question 1193037: For a quadrilateral ABCD, the measures of its angles are given below.
m∠A = (x + 14)°
m∠B = (2(x + 2))°
m∠C =
3/2
x − 13
°
m∠D =
7/3
x − 14
°Find x.
then, Find the measure of each angle (in degrees) of ABCD.
I'm not sure where to even start here. here's what I got so far: x+14+2x+4=360..and x+10+2x=360...so x+10=360..and i got 36
Click here to see answer by MathLover1(20850)  |
Question 1193071: Can i get step by step help with this question, not sure where to start here, im getting the wrong answer.
Consider ▱ABCD.
Suppose m∠A = (2x + 4)°and m∠B = (3x − 34)°.
Find x.
Find the measure of each angle (in degrees) of
▱ABCD.
m∠A =
°
m∠B =
°
m∠C =
°
m∠D =
Click here to see answer by josgarithmetic(39617) |
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925
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