SOLUTION: A piece of wire of length 36pi is cut into two unequal parts. Each part is then bent to form a circle. It is found that the total area of the two circle is 80pi. Find the differenc

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Question 891678: A piece of wire of length 36pi is cut into two unequal parts. Each part is then bent to form a circle. It is found that the total area of the two circle is 80pi. Find the difference in radius of two circles.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Circumference:
C%5B1%5D%2BC%5B2%5D=36pi
2pi%2AR%5B1%5D%2B2pi%2AR%5B2%5D=36pi
1.R%5B1%5D%2BR%5B2%5D=18
.
.
.
Area:
pi%2AR%5B1%5D%5E2%2Bpi%2AR%5B2%5D%5E2=80pi
2.R%5B1%5D%5E2%2BR%5B2%5D%5E2=80
From eq. 1,
R%5B1%5D=18-R%5B2%5D
Substitute into eq. 2,
%2818-R%5B2%5D%29%5E2%2BR%5B2%5D%5E2=80
324-36R%5B2%5D%2BR%5B2%5D%5E2%2BR%5B2%5D%5E2=80
2R%5B2%5D%5E2-36R%5B2%5D%2B244=0
R%5B2%5D%5E2-18R%5B2%5D%2B122=0
Complete the square,
R%5B2%5D%5E2-18R%5B2%5D%2B81%2B122=81
%28R%5B2%5D-9%29%5E2=-41
There's a problem here. The solution will be a complex number and not a real number.
Check the problem setup and make sure your values are correct.