SOLUTION: Solve for x: A.) Log(base 3)4 + log(base 3)5 = log(base 3)(4x+5) B.)log(base 7)6 -log(base 7)(x-1) = log(base 7)3 C.)3log(base x)4 = 2

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Question 67383This question is from textbook Advanced mathematics
: Solve for x:
A.) Log(base 3)4 + log(base 3)5 = log(base 3)(4x+5)
B.)log(base 7)6 -log(base 7)(x-1) = log(base 7)3
C.)3log(base x)4 = 2 This question is from textbook Advanced mathematics

Answer by algebrapro18(249) (Show Source):
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A.) Log(base 3)4 + log(base 3)5 = log(base 3)(4x+5)
Log(base 3)20 = log(base 3)(4x+5)
Log(base 3)20 - log(base 3)(4x+5) = 0
Log(base 3)20/(4x+5) = 0
3^0 = 20/(4x+5)
1 = 20/(4x+5)
4x+5 = 20
4x = 15
x = 15/4

B.)log(base 7)6 -log(base 7)(x-1) = log(base 7)3
log(base 7)6/(x-1) = log(base 7)3
log(base 7)6/(x-1) - log(base 7)3 = 0
log(base 7)6/3(x-1) = 0
7^0 = 6/3(x-1)
1 = 6/3(x-1)
3x-3 = 6
3x = 0
x = 3

C.)3log(base x)4 = 2
log(base x)64 = 2
x^2 = 64
x = +/- 8