Question 67230This question is from textbook Advanced mathematics
: The cook had x poinds of food in the store house, and this would feed y workers for d days. Then 50 more workers arrived in camp. How many days would the cook's food last since (y+50) workers must now be fed?
This question is from textbook Advanced mathematics
Answer by ptaylor(2198)   (Show Source):
You can put this solution on YOUR website! The cook had x poinds of food in the store house, and this would feed y workers for d days. Then 50 more workers arrived in camp. How many days would the cook's food last since (y+50) workers must now be fed?
THE ORIGINAL SOLUTION WAS NOT CORRECT----I'VE TRIED TO MAKE THE CORRECTIONS IN CAPS------ALSO, SEE PROBLEM 67684
LET Z=NUMBER OF DAYS THE FOOD WILL LAST WHEN (Y+50) WORKERS ARE BEING FED
Well, we know that x/y pounds will feed one worker for d days
And we also know that x/(yd) will feed one worker for one day
But we now have (y+50) workers
(x/(yd))(y+50) WILL FEED (Y+50) WORKERS FOR ONE DAY
So,IN Z DAYS, when (x/(yd))(y+50)(Z) equals x, then all the food is gone. So here's our equation to solve and we solve for d (NOT D BUT Z):
(x/(yd))(y+50)(Z)=x multiply both sides by yd
x(y+50)(Z)=xyd divide both sides by xy (NOT XY BUT X(Y+50)
Z=XYD/X(Y+50)
Z=YD/(Y+50)----------------CORRECT ANSWER
(x(y+50))/xy=xyd/xy simplify(NO!!!!!!!!!!)
(y+50)/y=d or (NO!!!!!!!!!!!!!)
d=(y+50)/y Let's check our dimensions(NO!!!!!!!!!!)
days=(workers-DAYS)/(workers=days
Hope this helps-----ptaylor
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