SOLUTION: 2log7^x = 4

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Question 66558This question is from textbook Advanced mathematics
: 2log7^x = 4 This question is from textbook Advanced mathematics

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x:
2log%28%287%29%29%5Ex+=+4 Divide both sides by 2.
log%28%287%29%29%5Ex+=+2 Apply the power rule for logarithms.
xlog%287%29+=+2 Divide both sides by log(7)
x+=+2%2Flog%28%287%29%29 Evaluate.
x+=+2.366589