SOLUTION: What is the eighth term of the geometric sequence whose first three terms are 3, 6, and 12 Thanks
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Question 333344
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What is the eighth term of the geometric sequence whose first three terms are
3, 6, and 12 Thanks
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Tutorteddy.Com(12)
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nth term Tn = ar^(n-1), where a is first term, Tn is nth term and r is the common ratio.
Here, r = 6/3 = 2.
Hence, 8th term = 3 X 2^(8 - 1) = 3 X 2^7 = 3 X 128 = 384