SOLUTION: How do you find the area of an isosceles trapezoid with legs = 10, shorter base = 10 and base angles = 60 degrees?

Algebra ->  Formulas -> SOLUTION: How do you find the area of an isosceles trapezoid with legs = 10, shorter base = 10 and base angles = 60 degrees?      Log On


   



Question 253197: How do you find the area of an isosceles trapezoid with legs = 10, shorter base = 10 and base angles = 60 degrees?
Answer by drk(1908) About Me  (Show Source):
You can put this solution on YOUR website!
First, draw an isosceles trapezoid with the question information included.
--
Second, draw an altitude from the top vertex on the left to the bottom, long base, and then do the same on the right top vertex. We have created 2 right (30-60-90) triangles. The height becomes 5sqrt(3) and the long base will become 20; remember that the side opposite the 30 degree angle is 1/2 the hypotenuse of 10 = 5.
--
Third find the area as
A+=%281%2F2%29%2A%2810%2B20%29%2A5%2Asqrt%283%29
A+=+75sqrt%283%29