SOLUTION: Line RQ bisects line DE at S. If DS = 10 + 3x and ES = -2 + 6x, find DE

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Question 1196524: Line RQ bisects line DE at S. If DS = 10 + 3x and ES = -2 + 6x,
find DE
Found 2 solutions by MathLover1, ewatrrr:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

if line RQ+bisects line DE at S, than +DS+=+ES+

if DS+=+10+%2B+3x and ES+=+-2+%2B+6x, than

10+%2B+3x+=-2+%2B+6x.........solve for x
10+%2B+2=+6x-3x
12=+3x
x=4

now find DS+=+10+%2B+3x
DS+=+10+%2B+3%2A4=22+=>ES+=22

then
DE=+DS%2BES+
DE=22%2B22
DE=+44


Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!

Hi  
Problem States:
Line RQ bisects line DE at S.
D_______S________E   | S is the point that bisects DE
That is:  DS = ES
If DS = 10 + 3x and ES = -2 + 6x 
 -2 + 6x =  10 + 3x
   x = 4
find DE
Substituting x = 4
DE = 22 + 22 = green%2844%29+
 
Wish You the Best in your Studies.