SOLUTION: With MN ∥ QP and ∠M ≅ ∠Q, MNPQ is a right trapezoid. Find the following.
m∠P in degrees, if m∠MNP − m∠P = 56°
m∠P =
the length of side NP (in cm),
if MN =
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-> SOLUTION: With MN ∥ QP and ∠M ≅ ∠Q, MNPQ is a right trapezoid. Find the following.
m∠P in degrees, if m∠MNP − m∠P = 56°
m∠P =
the length of side NP (in cm),
if MN =
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Question 1193157: With MN ∥ QP and ∠M ≅ ∠Q, MNPQ is a right trapezoid. Find the following.
m∠P in degrees, if m∠MNP − m∠P = 56°
m∠P =
the length of side NP (in cm),
if MN = 14 cm, MQ = 15 cm, and PQ = 22 cm
NP = ? cm
Angles M and Q are the right angles; the sum of angles N and P is 180 degrees. Given that angle N is 56 degrees more than angle P,
x = angle P
x+56 = angle N
x+x+56=180
2x=124
x=62
ANSWER 1: Angle P is 62 degrees
Drop a perpendicular from N to QP, forming a right triangle with hypotenuse NP. The legs of the triangle are MQ=15 and QP-MN=8; the Pythagorean Theorem tells us the hypotenuse is 17.
