SOLUTION: Rhombus named ABCD with a diagonals AC and DB. Given: AC = 18 and DB = 8 Find: AE DE AD

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Question 1193122: Rhombus named ABCD with a diagonals AC and DB. Given: AC = 18 and DB = 8
Find:
AE
DE
AD
Answer by MathLover1(20850) About Me  (Show Source):
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Given: AC+=+18+and DB+=+8
Find:
AE
DE
AD
A rhombus is a quadrilateral with both pairs of opposite sides parallel and all sides the same length, i.e., an equilateral parallelogram.

intersection point of diagonals: E
right triangle AEB=AED, and leg AE=18%2F2=9
DE=8%2F2=4
side length is equal to hypothenuse of the right triangle AEB or AED:
AD=sqrt%289%5E2%2B4%5E2%29
AD=sqrt%2881%2B16%29
AD=9.85+ approximately