SOLUTION: find the dimensions and maximum area of a rectangle if its perimeter is 40 centimeters Pls help I need it

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Question 1180587: find the dimensions and maximum area of a rectangle if its perimeter is 40 centimeters
Pls help I need it

Found 2 solutions by MathLover1, Theo:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

If the length =x and the width =y then the perimeter
P=40
P=2x%2B2y=40
x%2By=20
y=20-x
As for the area A
A=x%2Ay.........substitute y
A=x%2820-x%29
A=20x-x%5E2
And we have to find an extreme for that
A'=20-2x by setting the derivative to =0
20x-2x=0
2%2810-x%29x=0
x=10cm
then
y=20-x
y=10cm


Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
the perimeter is 40 centimeters.
the perimeter is equal to 2L + 2W.
L = length
W = width.
when L = W, you can replace L with W or W with L to get:
perimeter = 4L or 4W.
formula for perimeter becomes 4L = 40 or 4W = 40.
this makes L = 10 and W = 10.
the area is L * W = 10^2 = 100
that should be the maximum area since the maximum area of a rectangle is when the rectangle is a square.
to confirm, you can try any other combination of 2L + 2W = 40 and then find the area.
the possible combinations are shown below:
you can see that the maximum area is when L = W.