SOLUTION: Given x^2+y^2+2x-10y+30=0. Find the measure of the radius.

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Question 1171744: Given x^2+y^2+2x-10y+30=0. Find the measure of the radius.
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!

+x%5E2%2By%5E2%2B2x-10y%2B30=0+

Observe the above for a moment, and re-write it as:
+%28x%5E2%2B2x%2B1%29%2B%28y%5E2-10y%2B25%29%2B4=0+

Although you should by now notice there is going to be a problem, let's continue...
++%28x%2B1%29%5E2+%2B+%28y-5%29%5E2+%2B+4+=+0+
++%28x%2B1%29%5E2+%2B+%28y-5%29%5E2+=+-4+
The form of a circle centered at (h,k) with radius r, is
+%28x-h%29%5E2+%2B+%28y-k%29%5E2+=+r%5E2+ and we have r%5E2+=+-4+.
This circle has a radius of 2i (2 times the imaginary unit).
This is probably NOT what you wanted. Check your post carefully
for accuracy and re-post with corrections or clarification.