SOLUTION: The vertices of triangle ABC are A(1,5), B(7,-1) and C(-2,-2). What is the perimeter of this triangle?

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Question 1153139: The vertices of triangle ABC are A(1,5), B(7,-1) and C(-2,-2). What is the perimeter of this triangle?
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
The perimeter is the sum of the lengths of each side:

AB = +sqrt%28%287-1%29%5E2%2B%28-1-5%29%5E2%29+=+sqrt%2836%2B36%29+=+6sqrt%282%29+ ... or approx 8.485
BC = +sqrt%28%28-2-7%29%5E2%2B%28-2-%28-1%29%29%5E2%29+=+sqrt%2881%2B1%29+=+sqrt%2882%29+ ... approx 9.055
CA = +sqrt%28%281-%28-2%29%29%5E2%2B%285-%28-2%29%29%5E2%29+=+sqrt%289%2B49%29+=+sqrt%2858%29+ ... approx 7.616


Adding the three lengths (and assuming my math is correct):

perimeter = 25.156 units