SOLUTION: an astronaut on the surface of the moon jumps off a 41.6 ft tall cliff. the equation that gives the astronaut height about lunar surface is h=2.6t^2+41.6 when does the astronaut hi

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Question 1151731: an astronaut on the surface of the moon jumps off a 41.6 ft tall cliff. the equation that gives the astronaut height about lunar surface is h=2.6t^2+41.6 when does the astronaut hit the lunar surface?
Found 2 solutions by ikleyn, josmiceli:
Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.

The equation is written incorrectly,

which shows that you don't know and don't understand the subject.


Twice and thrice check with your source.


/\/\/\/\/\/\/\/\/

Below is the source from me for you to learn the subject.


If you have the height given to you as the function of time in the form


    h(t) = -at^2 + bt + c,    (1)


where "a", "b" and "c" are real numbers, a > 0, then



    (a)  the initial height is equal to the coefficient "c" value;


    (b)  the initial velocity is the coefficient  "b" in the formula;


    (c)  the coefficient "a" value is half of the gravity acceleration.




    (d)  To find the height at the time moment "t", simply substitute the value of "t" into the formula (1) and calculate.


    (e)  To find the time "t" when the height has a given value h = h%5B0%5D, substitute  h = h%5B0%5D into equation (1)

         and solve equation  


             h(t) = -at^2 + bt + c = h%5B0%5D.    (2)



    (f)  To find the time when the height is maximal, use the formula


             t%5Bmax%5D = b%2F%282a%29.      (3)



    (g)  To find the maximal height, substitute the time value  t= t%5Bmax%5D  of the formula (3)  into the formula (1).

What's all you need to know.

To answer your questions,  use my instructions and make calculations on your own.

---------------

To see numerous examples of solved problems,  look into the lessons
    - Problem on a projectile moving vertically up and down
    - Problem on an arrow shot vertically upward
    - Problem on a ball thrown vertically up from the top of a tower
    - Problem on a toy rocket launched vertically up from a tall platform
in this site.

Consider these lessons as your textbook,  handbook,  tutorials and  (free of charge)  home teacher.
Read them attentively and learn how to solve this type of problems once and for all.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic "Projectiles launched/thrown and moving vertically up and dawn".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.



Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+h+=+-2.6t%5E2+%2B+41.6+ ft
Note that the 1st term should be negative since
this is gravity acting downward
When the astronaut hits the surface, +h+=+0+
+-2.6t%5E2+%2B+41.6+=+0+
+-2.6t%5E2+=+-41.6+
+t%5E2+=+16+
+t+=+4+
Astronaut hits the surface in 4 sec