SOLUTION: My second question is a rectangular picture with dimensions 5in by 8in is surrounded by a frame of uniform width. The combined area of the frame and picture is 180in squared find t

Algebra ->  Formulas -> SOLUTION: My second question is a rectangular picture with dimensions 5in by 8in is surrounded by a frame of uniform width. The combined area of the frame and picture is 180in squared find t      Log On


   

Question 1123596: My second question is a rectangular picture with dimensions 5in by 8in is surrounded by a frame of uniform width. The combined area of the frame and picture is 180in squared find the width of the frame? Thank you for any help you can provide
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Let represent the width of the frame. Since there is a frame around all four sides, there are two of these dimensions added to each of the length and width of the original picture, so the length with the frame is , and the width with the frame is , and since the total area is 180 inē:



Multiply it out, put the equation in standard form, and solve the quadratic for the positive value of . The negative root is discarded because a negative number for a measurement of length is nonsense.


John

My calculator said it, I believe it, that settles it